The sum \displaystyle\sum_{k=1}^{\infty}\frac{1}{k^3+6k^2+8k} can be expressed as \dfrac{a}{b}, where a and b are relatively prime positive integers. What is a+b?
Answer Choices:
A. 89
B. 97
C. 102
D. 107
E. 129
The sum \displaystyle\sum_{k=1}^{\infty}\frac{1}{k^3+6k^2+8k} can be expressed as \dfrac{a}{b}, where a and b are relatively prime positive integers. What is a+b?
Answer Choices:
A. 89
B. 97
C. 102
D. 107
E. 129