The number 21 !=51,090,942,171,709,440,000 has over 60,000 positive integer divisors. One of them is chosen at random. What is the probability that it is odd?

**Answer Choices**

A. \dfrac{1}{21}

B. \dfrac{1}{19}

C. \dfrac{1}{18}

D. \dfrac{1}{2}

E. \dfrac{11}{21}