The fraction
\dfrac{1}{99^{2}}=0 . \overline{b_{n-1} b_{n-2} \ldots b_{2} b_{1} b_{0}}
where n is the length of the period of the repeating decimal expansion. What is the sum b_{0}+b_{1}+\cdots+b_{n-1} ?
Answer Choices
A. 874
B. 883
C. 887
D. 891
E. 892