For all integers n greater than 1 , define a_{n}=\dfrac{1}{\log _{n} 2002}. Let b=a_{2}+a_{3}+a_{4}+a_{5} and c=a_{10}+a_{11}+a_{12}+a_{13}+a_{14}. Then b-c equals
Answer Choices
A. -2
B. -1
C. \dfrac{1}{2002}
D. \dfrac{1}{1001}
E. \dfrac{1}{2}