Quadrilateral A B C D has right angles at B and C, \triangle A B C \sim \triangle B C D, and A B>B C. There is a point E in the interior of A B C D such that \triangle A B C \sim \triangle C E B and the area of \triangle A E D is 17 times the area of \triangle C E B. What is \dfrac{A B}{B C} ?
Answer Choices
A. 1+\sqrt{2}
B. 2+\sqrt{2}
C. \sqrt{17}
D. 2+\sqrt{5}
E. 1+2 \sqrt{3}