\mathrm{ACE} is divided at \mathrm{C} in the ratio 2: 3. The two semicircles, A B C and C D E, divide the circular region into an upper (shaded) region and a lower region. The ratio of the area of the upper region to that of the lower region is
Answer Choices
A. 2: 3
B. 1: 1
C. 3: 2
D. 9: 4
E. 5: 2