CAYLEY 2004 Problem 19

\displaystyle\frac12+\frac{2^1}{2^2}+\frac{2^2}{2^3}+\cdots+\frac{2^{2002}}{2^{2003}}+\frac{2^{2003}}{2^{2004}} is equal to

Answer Choices
A. 1002
B. 501
C. \displaystyle\frac{1}{2^{2004}}
D. 2004
E. \displaystyle\frac{2004}{2^{2004}}