CAYLEY 2011 Problem 11

The operation “\nabla” is defined by (a,b)\nabla(c,d)=ac+bd.
For example (1,2)\nabla(3,4)=(1)(3)+(2)(4)=11.
The value of (3,1)\nabla(4,2) is

Answer Choices
A. 10
B. 11
C. 13
D. 14
E. 24