Triangle ABC is isosceles with AB=AC and BC=65\:cm. P is a point on BC such that the perpendicular distances from P to AB and AC are 24\:cm and 36\:cm, respectively. The area of \delta{ABC}, in cm^2, is
Answer Choices
A. 1254
B. 1640
C. 1950
D. 2535
E. 2942