If a and b are positive integers such that \displaystyle\frac1a+\frac{1}{2a}+\frac{1}{3a}=\frac{1}{b^2-2b}, then the smallest possible value of a+b is
Answer Choices
A. 8
B. 6
C. 96
D. 10
E. 50
If a and b are positive integers such that \displaystyle\frac1a+\frac{1}{2a}+\frac{1}{3a}=\frac{1}{b^2-2b}, then the smallest possible value of a+b is
Answer Choices
A. 8
B. 6
C. 96
D. 10
E. 50