FERMAT 2011 Problem 18

Past Contests FERMAT FERMAT - 2011
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1

A 4\times4 square piece of paper is cut into two identical pieces along its diagonal. The resulting triangular pieces of paper are each cut into two identical pieces.

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Each of the four resulting pieces is cut into two identical pieces. Each of the eight new resulting pieces is finally cut into two identical pieces. The length of the longest edge of one of these final sixteen pieces of paper is

Answer Choices
A. 1
B. 2
C. \frac{1}{2}
D. \frac{1}{\sqrt2}
E. 2\sqrt2