FERMAT 2020 Problem 16

Suppose that x and y are real numbers with -4 \leq x \leq-2 and 2 \leq y \leq 4. The greatest possible value of \frac{x+y}{x} is

Answer Choices
A. 1
B. -1
C. -\frac{1}{2}
D. 0
E. \frac{1}{2}