An aluminum can in the shape of a cylinder is closed at both ends. Its surface area is 300 \mathrm{~cm}^{2}. If the radius of the can were doubled, its surface area would be 900 \mathrm{~cm}^{2}. If instead the height of the can were doubled, what would its surface area be? (The surface area of a cylinder with radius r and height h is equal to 2 \pi r^{2}+2 \pi r h).
Answer Choices
A. 450 \mathrm{~cm}^{2}
B. 600 \mathrm{~cm}^{2}
C. 750 \mathrm{~cm}^{2}
D. 375 \mathrm{~cm}^{2}
E. 300 \mathrm{~cm}^{2}