For n \geq 2, let \omega(n) denote the number of distinct prime factors of n. We set \omega(1) = 0. Compute the absolute value of
\sum_{n=1}^{160} (-1)^{\omega(n)} \left\lfloor \frac{160}{n} \right\rfloor.
For n \geq 2, let \omega(n) denote the number of distinct prime factors of n. We set \omega(1) = 0. Compute the absolute value of
\sum_{n=1}^{160} (-1)^{\omega(n)} \left\lfloor \frac{160}{n} \right\rfloor.